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A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle inclination $30 °$ . The centre of mass of cylinder has speed of 4 m/s. The distance travelled by the cylinder on the incline surface will be : $(Take g = 10 m / s^{2})$

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2.2 m

1.6 m

1.2 m

2.4 m

answer is D.

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Detailed Solution

$\frac{1}{2} {mv}^{2} (1 + \frac{K^{2}}{R^{2}}) = mgh \Rightarrow 8 (1 + \frac{1}{2}) = 10 h$

$h = 1.2 m$

$\frac{h}{l} = \sin 30^{\circ}; l = 2.4 cm$

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