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A solid cylinder of mass 50kg and radius 0.5m is tree to rotate about the horizontal axis. A massless string is wound round the cylinder with one end attached to it and other hanging freely. Tension in the string required to produce an angular acceleration of 2 radian 2s^–2 is

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78.5 N

157 N

25 N

50 N

answer is D.

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Detailed Solution

Given, m = 50kg, r = 0.5m, $α$ = 2rad/s²

We know torque is

$τ = T \times r = I \times α$

$\Rightarrow T x 0.5 = \frac{50 x {(0.5)}^{2}}{2} x 2$
T = 25 N

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