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Q.

A solid cylinder of mass 12 kg is rolling on a rough horizontal surface with velocity 4 ms–1. It collides with a horizontal spring of force constant 200 Nm–1. The maximum compression produced in the spring will be :-

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a

0.7 m

b

0.4 m

c

0.6 m

d

1.2 m

answer is D.

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Detailed Solution

At maximum compression of spring, total kinetic energy of rolling cylinder will be converted into potential energy of the spring. 

so, 12mv21+K2R2=12kx2 

⇒ 12×12×421+12=12×200×x2 

on solving, we get x=1.2 m 

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