A solid cylinder of radius ‘R’ carrying current ‘i’. The magnetic induction at a distance $\frac{R}{2}$ from its axis is

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$\frac{μ_{o} i}{2 π R^{2}}$

$\frac{μ_{o} i}{4 π R^{2}}$

$\frac{2 μ_{0} i}{π R}$

$\frac{μ_{o} i}{4 π R}$

answer is D.

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Detailed Solution

Inside point
$\begin{array}{l} B = \frac{μ_{o} i}{2 π R^{2}} \times r \\ B = \frac{μ_{o} i}{2 π R^{2}} \times \frac{R}{2} \\ = \frac{μ_{o} i}{4 π R} \end{array}$

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