A solid cylinder S and a hollow cylinder T of same mass and same outer radius have a thin thread wound over them. One end of each thread is fixed to the same ceiling. They are initially held at rest with their axis horizontal and parallel to each other, at same height above ground. tf the cylinders are released simultaneously with strings taut then the correct statement is :

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Both will reach ground together

S will reach ground earlier than f

For small height S will reach earlier and for large height T will reach earlier

T will reach ground earlier than S

answer is A.

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Detailed Solution

mg -T = ma
$TR = Iα and a = Rα$
Solving, we get
$a = \frac{mg}{(m + \frac{I}{R^{2}})}$
So, due to greater 1 of hollow cylinder, its acceleration (a) is lesser and hence, it will fall slowly than solid cylinder.

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