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A solid disc of radius 0.4 m can rotate about an axis passing through O its centre and perpendicular to the plane of the disc. Initially the disc is not rotating. Now a torque $τ$ is applied on the disc which varies with time as shown in the figure. Then angular momentum of the disc at t = 3s is

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$12 N - m - S$

$15 N - m - S$

$10 N - m - S$

$20 N - m - S$

answer is B.

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Detailed Solution

Charge in angular momentum

= Angular impulse = Area under $τ - t$ graph.

$∴ L - 0 = \frac{1}{2} \times 3 \times 10 N - m - S$

$\Rightarrow L = 15 N - m - S$

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