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A solid disc of radius $20 c m$ and mass $10 k g$ is rotating with an angular velocity of $600 r p m$ about an axis normal to its circular plane and passing through its centre of mass. The retarding torque required to bring the disc to rest in $10 s$ is $a π × 10 − 1 N m$ . The value of $a$ is _______

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answer is 4.

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Detailed Solution

τ = M R 2 2 α; w t = α ⇒ 20 π 10 = α ∵ w = 600 × π 30 r a d / s

⇒ α = 2 π r a d / s 2 ⇒ τ = 12 × 10 × 4100 × 2 π = 0.4 π

= 4 π × 10 − 1 N m

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