A solid floats in a liquid in a partially dipped position, then

I) The solid exerts a force equal to its weight on the liquid

II) The liquid exerts a force of buoyancy on the solid which is equal to the weight of the solid

III) The weight of the displaced liquid equals the weight of the solid

IV) The weight of the dipped part of the solid is equal to the weight of the displaced liquid

Given that a solid float in a liquid in a partially dipped position.

We know weight of floating body whether it is completely immersed or partially immersed must be equal to weight of liquid displaced according to principle of buoyancy (Archimedes principle).

            We get following as true

            (i) The solid exerts a force equal to its weight on the liquid.

            (ii) Liquid exerts a force of buoyancy on the solid which is equal to the weight of solid.

            (iii) The weight of the displaced liquid is equal to the weight of solid.