A solid having density of $9 \times 10^{3} k g m^{- 3}$ forms face centres cubic crystals of edge length $200 \sqrt{2} p m$ What is the molar mass of the solid?

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$0.0432 k g m o l^{- 1}$

$0.0216 k g m o l^{- 1}$

$0.4320 k g m o l^{- 1}$

$0.0305 k g m o l^{- 1}$

answer is D.

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Detailed Solution

$\begin{array}{l} δ = \frac{Z \times M}{a^{3} N_{A}} \Rightarrow 9 \times 10^{3} = \frac{4 \times M}{{(200 \sqrt{2} \times 10^{- 12})}^{3} \times 6 \times 10^{23}} \\ M = 0 .0305 kg / mole \end{array}$

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