Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

A solid iron cuboidal block of dimensions 4.4 m × 2.6 m × 1m is recast into a hollow cylindrical pipe of internal radius 30 cm and thickness 5 cm. What is the length of the pipe?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

113m

112m

110m

102m

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

It is given that the solid iron cuboidal block of dimensions

l = 4.4

b = 2.6

h = 1

m.
And radius and thickness of hollow cylindrical pipe are

r = 30

= \frac{30}{100} m

, and

b = 2.6

cm respectively.
Let the length of the hollow cylindrical pipe is

h ′

.
The external radius of hollow cylindrical pipe is,

R = r + t R = 30 + 5 R = 35 cm

R = \frac{35}{100} m

The volume of the hollow cylinder is given by,

V = π R 2 − r 2 h

.
Equating the volume of cuboid and the volume of hollow cylinder to obtain the height. length of the pipe. We get,

l b h = π R 2 − r 2 h ′ 4.4 m × 2.6 m × 1 m = π 35 m 100 2 − 30 m 100 2 h ′ 11.44 = π 0.0325 h ′ 11.44 = 3.14 × 0.0325 h ′

h ′ = 11.44 3.14 × 0.0325 h ′ = 112 m

The length of the pipe is 112 m.
Therefore, 2 is the correct option.

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE