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Q.

A solid iron cuboidal block of dimensions 4.4 m × 2.6 m × 1m is recast into a hollow cylindrical pipe of internal radius 30 cm and thickness 5 cm. What is the length of the pipe?


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a

113m

b

112m

c

110m

d

102m 

answer is B.

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Detailed Solution

It is given that the solid iron cuboidal block of dimensions l=4.4  m, b=2.6  m, h=1  m.
And  radius and thickness of hollow cylindrical pipe are r=30  cm =30100m, and b=2.6  cm respectively.
Let the length of the hollow cylindrical pipe is h  .
The external radius of hollow cylindrical pipe is,
R=r+t R=30+5 R=35cm  
R=35100m
The volume of the hollow cylinder is given by, V=π R 2 r 2 h  .
Equating the volume of cuboid and the volume of hollow cylinder to obtain the height. length of the pipe. We get,
lbh=π R 2 r 2 h 4.4m×2.6m×1m=π 35m 100 2 30m 100 2 h 11.44=π 0.0325 h 11.44=3.14× 0.0325 h   h = 11.44 3.14×0.0325 h =112m  
The length of the pipe is 112 m.
Therefore, 2 is the correct option.
 
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