AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A solid is in the form of a cone of vertical height $9 cm$ mounted on the top base of a right circular cylinder of height $40 cm$ . The radius of the base of the cone and that of the cylinder are both equal to $7 cm$ . Find the weight of the solid if $1 c m^{3}$ of the solid weighs $4 gm .$

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

26.488 kg

25.488 kg

24.488 kg

23.488 kg

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Given a cone of vertical height

9 cm

mounted on the top base of a right circular cylinder of height

40 cm

and radius of the base of the cone and that of the cylinder are both equal to

7 cm

Now,
Volume of Cylinder of Radius "R"(7cm) and height "h"(40cm)

= π R^{2} h

Volume of a cone

= \frac{1}{3} π r^{2} h

, where

r

(7cm) is the radius of the base of the cone and

h

(9cm) is the height.
Volume of the solid

=

Volume of the cylindrical part

+

Volume of conical part
So, the Volume of the solid =

(\frac{22}{7} ​ \times 7 \times 7 \times 40) + (\frac{1}{3} ​ \times \frac{22}{7} \times 7^{2} \times 9)

\Rightarrow 6160 + 462

\Rightarrow 6622 c m^{3}

According to the question,

1 {cm}^{3}

4 gm

\Rightarrow 6622 {cm}^{3}

6622 \times 4

\Rightarrow 6622 {cm}^{3} = 26488 g

\Rightarrow 6622 {cm}^{3} = 26.488 kg

Therefore, the weight of the solid is

26.488 kg

.
Hence, the correct option is 1.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!