A solid metallic sphere has a charge +3Q . Concentric with this sphere is a conducting spherical shell having charge -Q . The radius of the sphere is a and that of the spherical shell is b (b>a). What is the electric field at a distance R (a<R<b) from the centre.

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$\frac{3 Q}{2 π ε_{0} R}$

$\frac{3 Q}{4 π ε_{0} R^{2}}$

$\frac{Q}{2 π ε_{0} R}$

$\frac{4 Q}{4 π ε_{0} R^{2}}$

answer is C.

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Detailed Solution

Electric field at a distance R is only due to sphere because electric field due to shell inside it is always zero. Hence electric field
$\large =\frac{1}{{4\pi {\varepsilon _0}}}.\frac{{3Q}}{{{R^2}}}$

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