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A solid objects floats in a liquid lying in a stationary container. The object is in stable
equilibrium and it is partially inside the liquid and partially in air. Regarding this situation choose the correct option(s)

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Force exerted by the liquid on the solid object is greater than the weight of the object

Force exerted by the liquid on the bottom of the container is equal to the combined weight of the liquid and the solid object.

The centre of gravity of the object is below the centre of buoyancy

Force exerted by the liquid on the bottom of the container is greater than the weight of the liquid

answer is A, B, C.

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Detailed Solution

Force due to liquid is buoyancy = Weight of floating object + Thrust on the body by atmospheric air.
For stable equilibrium of floating object, centre of buoyancy must lie above the centre of gravity.

Force exerted by the liquid on the bottom of container = Weight of liquid + Force of buoyancy on the floating object .

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