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A solid rectangular piece of iron measures $6 m$ by $6 cm$ by $2 cm$ Find the weight of this piece, if $1 cm 3$ of iron weighs $8 gm .$

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43.8kg

57.6kg

76.7kg

65.7kg

answer is B.

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Detailed Solution

It is given a solid rectangular piece of iron measuring

6 m

6 cm

2 cm

.
Converting the length of the rectangular piece from 6

m

to equivalent cm,

6 m = 6 × 100 c m ⇒ 6 m = 600 c m

(1m=100cm)
We know the formula for volume of the cuboid is given by:

V = l × b × h

Volume of the iron piece =

600 c m × 6 c m × 2 c m

⇒ V o l u m e o f t h e i r o n p i e c e = 7200 c m 3

The total weight of the piece will be obtained by multiplying the volume of the piece by the weight of

1 c m 3

.
Total weight =

7200 × 8

⇒ T o t a l w e i g h t = 57600 g m

Converting the total weight of piece from grams to equivalent kg,

57600 g = 576001000 k g ⇒ 57600 g = 57.6 k g

(1kg=1000g)
Thus, the weight of the piece is

57.6 k g

.
Hence option (2) is correct.

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