Q.

A solid shell loses half its weight in water. Relative density of shell is 5.0. What fraction of its volume is hollow?

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a

35

b

15

c

45

d

25

answer is A.

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Detailed Solution

Let x fraction of its volume is hollow. Then weight of shell

=(VxV)×5.0×1000×g

Weight of water displaced =V×1000×g

Weight of water displaced = loss in weight

V×1000×g=12(VxV)×5.0×1000×g

Solving this we get, x=35

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