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A solid sphere and a hollow sphere of same mass and radius rotate about their diameter with same K.E. If torques of equal magnitude are applied on them, the ratio of their angular displacement before they are brought to rest is

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3:5

5:3

2:3

$1 : 1$

answer is A.

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Detailed Solution

$k_{1} = τ_{1} θ_{1}$

$k_{2} = τ_{2} θ_{2}$

$\frac{k_{1}}{k_{2}} = \frac{τ_{1} θ_{1}}{τ_{2} θ_{2}}$

$θ_{1} : θ_{2} = 1 : 1$

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