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Q.

A solid sphere of mass 1.5 kg rolls on a frictionless horizontal surface, its centre of mass moving at a speed of 5 ms–1. Then it rolls up an incline of 300 to horizontal. The height attained by the sphere before it stops is (g = 10 ms–2)

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a

5 m

b

1.5m 

c

 1.75 m

d

3.65m

answer is C.

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Detailed Solution

x=?, m=1.5kg, v=5m/s, θ=30°

We know that,

12mv2+12Iω2=mgh

12mv2+1225mr2v2r2=mgh

m12v2+15v2=mgh

710v2=gh

h=7v210g=7×5210×10=1.75m

Hence the correct answer is 1.75m.

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