A solid sphere of mass M, radius R rests on a rough horizontal surface  $\mu =\frac{1}{2}$. A force F is applied at a height h above the centre of sphere horizontally as shown on figure at  t = 0.

If  $F=Mg/2,h=R/2$, linear velocity of sphere at t = 14 sec is  $75m{s}^{-1}$.

If   $F=Mg/2,h=R$, the magnitude of frictional force would be zero.

If  $F=Mg/2,h=R/2$ , frictional force acts in forward direction.

If   $F=Mg/2,h=R/2$, the sphere undergoes pure rolling.