A solid sphere rolls down two different inclined planes of the same height but of different inclinations:

$\text{ As }v=\sqrt{\frac{2gh}{1+\frac{I}{M{R}^2}}}$

Hence velocity is independent of the inclination of the plane and depends only on height h through which body descends. But because $t=\frac{1}{\sin \theta }\sqrt{\frac{2h}{g}\left(1+\frac{I}{M{R}^2}\right)}$ depends on the inclination also, hence greater the inclination lesser will be the time of descend. Hence, in present case, the speeds will be same (because h is same) but time is descend will be different (because of different inclinations)