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A solid uniform sphere rotating about its axis with kinetic energy $E_{1}$ is gently placed on a rough horizontal plane at time t=0, Assume that at time t = $t_{1}$ , it starts pure rolling and at that instant total KE of the sphere is $E_{2}$ . After some time t = $t_{2}$ , KE of sphere is $E_{3}$ Then

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$E_{1} > E_{2} = E_{3}$

$E_{1} > E_{2} > E_{3}$

$E_{1} = E_{2} = E_{3}$

$E_{1} < E_{2} < E_{3}$

answer is B.

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Detailed Solution

During impure rolling kinetic friction exists, loss takes place which reduces the kinetic energy. For pure rolling no loss of energy takes place.

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