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A solid XY kept in an evacuated sealed container undergoes decomposition to form a mixture of gases X and Y at temperature T. The equilibrium pressure is 10 bar in this vessel. KP for this reaction is:

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By Expert Faculty of Sri Chaitanya
a
25
b
100
c
10
d
5

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detailed solution

Correct option is A

XY(s)X(g)+Y(g) Equilibrium pressure =pX+pY=10bar

Since pX=pY we have pX=pY=5 bar . The value of equilibrium constant will be Kp=pXpY=(5bar)2=25bar2

 


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