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Q.

A solid XY kept in an evacuated sealed container undergoes decomposition to form a mixture of gases X and Y at temperature T. The equilibrium pressure is 10 bar in this vessel. $K_{P}$ for this reaction is:

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a

100

b

25

c

10

d

5

answer is A.

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Detailed Solution

$XY (s) ⇌ X (g) + Y (g)$ Equilibrium pressure $= p_{X} + p_{Y} = 10 bar$

Since $p_{X} = p_{Y}$ we have $p_{X} = p_{Y} = 5 bar$ . The value of equilibrium constant will be $K_{p} = p_{X} p_{Y} = (5 bar)^{2} = 25 {bar}^{2}$

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