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A solution containing $15.168 g$ of $S e_{x}$ in $200 g$ of benzene showed a depression in freezing point of 0.6 °C. If the molal depression constant of benzene is $5 K k g m o l^{- 1}$ and atomic weight of selenium is $79 u,$ the value of $\frac{x}{2}$ is

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answer is 4.

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Detailed Solution

$0.6 = 5 \times \frac{15.168}{79 x} \times \frac{1000}{200} \Rightarrow x = 8$

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