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Q.

A solution containing 25.6gm of sulphur dissolved in 1000gm of naphthalene gave a freezing point lowering of 0.680, then molecular formula of sulphur is (K_F for naphthalene = 6.8K kg mol^–1)

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a

S₆

b

S₈

c

S₂

d

S₄

answer is D.

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Detailed Solution

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$\begin{aligned} {ΔT}_{f} = K_{f} \cdot \frac{Wt}{Gmt} \cdot \frac{1000}{wt. of solvent} \\ \Rightarrow 0 .680 = 6 .8 \times \frac{25 .6}{x} \times \frac{1000}{1000} \end{aligned} x = 256 ∴ Molecular Mass of Sulphur = 256 g Hence, formula of sulphur = S_{8} $

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