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Q.

A solution containing 28 g of phosphorus in 315 g CS2 (b. p. 46.3° C) boils at 47.98° C. If Kb for CS2is 2.34 K kg mol−1'. The formula of phosphorus is (at. mass of P = 31).

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a

P3

b

P6

c

P4

d

P2

answer is B.

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Detailed Solution

ΔTb=1.68=2.34×28M315×1000

⇒ M=124

31×x=124

⇒ x=4

Hence P4

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