A solution containing 2g of a non–volatile solute in 20 g of water boils at 373.52 K. The molecular mass of the solute is ______ g mol^-1 . (Nearest integer)
Given , water boils at 373 K. K_b for water = 0.52K kg mol^-1

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answer is 100.

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Detailed Solution

$\begin{array}{l} {ΔT}_{b} = {ik}_{b} m ∵ i = 1 \\ 0.52 = 1 \times 0.52 \times \frac{2}{mol . wt} \times \frac{1000}{20} \\ mol . wt = 100 \end{array}$

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