A solution containing 62 g ethylene glycol in 250 g water is cooled to –10°C. If K_f for water is 1.86 K kg $m o l^{- 1}$ , the amount of water separated as ice is

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64 g

32 g

48 g

16 g

answer is D.

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Detailed Solution

$\begin{array}{l} Δ T_{f} = K_{f} \cdot m \\ Therefore, m = \frac{no. of moles of solute}{volume of solvent (Kg)} \\ 10 = 1.86 \times \frac{62 / 62}{W_{kg}} \\ W = 0.186 kg \\ Δ W = (250 - 186) = 64 gm \end{array}$

Therefore, the correct option is D

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