A solution containing 62 g ethylene glycol in 250g water is cooled to $-{10}^{0}C$ . If $K_f$  for water is 1.86 K kg $mo{l}^{-1}$ , the amount of water (in g ) separated as ice is 

$\Delta T_f=K_f\times \frac{W_2}{M_2}\times \frac{1000}{W_1}$

Where,  $W_1=$ mass of solvent $\left(H_{2}O\right)$ 
$W_2=$  mass of solute (ethylene glycol)
 $M_2=$ molar mass of solute
 $\therefore W_1=\frac{K_f\times W_2\times 1000}{\Delta T_f\times M_2}=\frac{1.86\times 62\times 1000}{10\times 62}=186g$
 $\therefore$Amount of water separated as ice =  
$\left(250-186\right)g=64$