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A solution containing $M n^{+ 2}$ is reacted with ‘v’ ml of 0.2 M $M n O_{4}^{-}$ in aqueous medium such
that the species comproportonate completely into $M n^{3 +}$ . The resultant solution consumed
50ml 0.1M Hypo iodometry. What can be concluded $(M n^{3 +} + I^{-} \to M n^{2 +} + I_{2})$

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The Eq. wt of $M n^{+ 3}$ is not same in both reactions

The first solution contains 4 millimoles of $M n^{+ 3}$

The no. of equivalents of $M n^{+ 3}$ is same in comproportionation and iodometry.

The value of ‘v’ is 5

answer is A.

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Detailed Solution

$M n^{2 +} + M n O_{4}^{-} \to M n^{3 +}$

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