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A solution contains 0.01M Zn⁺² and 0.01M Cu⁺² ions. The solution is saturated by passing H₂S gas in the solution. The sulphide ion concentration is 8.1 × 10^–21M. K_SP for ZnS and CuS are 3 × 10^–22 and 8 × 10^–36 respectively. which of the following will occur in solution

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CuS gets precipitated

ZnS get precipitated

Both Cu⁺² and Zn⁺² ions remain in the solution

Both CuS and ZnS get precipitated

answer is A.

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Detailed Solution

Determining the ionic product of ZnS

[Zn⁺²] [S^-2] = 10^-2 x 8.1 x 10^-21 = 8.1 x 10^-23

K_IP < K_sp ⇒ precipitation will not occur.

Determining the ionic product of CuS

[Cu⁺²] [S^-2] = 10^-2 x 8.1 x 10^-21 = 8.1 x 10^-23

K_IP > K_sp ⇒ precipitation will occur.

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