A solution Contains mixture of H₂SO₄ ,H₂C₂O₄ . 20 ml of this solution requires 40ml of $\frac{M}{10}$ NaOH for neutralization and 20ml of $\frac{N}{10}$ KMnO₄ for oxidation. The molarity of ${H_{2} C}_{2} O_{4}, H_{2} {SO}_{4}$ are

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0.05,0.1

0.05,0.05

0.1,0.05

0.1,0.1

answer is D.

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Detailed Solution

Let Molarity of $H_{2} S 0_{4} = M_{1}$
Let Molarity of $H_{2} C_{2} O_{4} = M_{2}$
No. of milli eq of $H_{2} {SO}_{4} + H_{2} C_{2} O_{4}$ = No of millieq of NaOH
$\begin{array}{l} 20 (2 M_{1} + 2 M_{2}) = 40 \times \frac{1}{10} \\ 40 (M_{1} + M_{2}) = 4 \\ M_{1} + M_{2} = 0 .1 - - - - (1) \end{array}$
No. of millieq of $H_{2} C_{2} O_{4}$ = No of millieq of ${KMnO}_{4}$
$\begin{array}{l} 20 (2 M_{2}) = 20 \times \frac{1}{10} \\ 40 \times M_{2} = 2 \\ M_{2} = 0 .05 M - - - (2) \\ M_{1} + M_{2} = 0 .1 \\ M_{1} + 0 .05 = 0 .1 \\ M_{1} = 0 .1 - 0 .05 = 0 .05 \end{array}$