A solution has a 1: 4 mole ratio of pentane to hexane. The vapour pressure of the pure hydrocarbons at 20^oC are 440 mmHg for pentane and 120 mmHg for hexane. The mole fraction of pentane in the vapour phase would be:

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0.549

0.478

0.200

0.786

answer is D.

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Detailed Solution

$P_{T} = P_{p}^{0} x_{p} + P_{h}^{0} x_{h} = 440 \times \frac{1}{5} + 120 \times \frac{4}{5} \begin{array}{l} = 88 + 96 = 184; P_{p}^{0} x_{p} = y_{p} P_{T}; \frac{88}{184} = y_{p} \\ y_{p} = 0 .478 \end{array}$

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