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Q.

A solution has been prepared by mixing $5.6 mL$ of alcohol with $75 mL$ of water. Calculate the percentage (by volume) of alcohol in the solution.

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a

6.95 %

b

6.97 %

c

5.97 %

d

5.96 %

answer is A.

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Detailed Solution

The percentage (by volume) of alcohol in the solution is

6.95 %

.
A solution is made up with solvent and solute. Here water is solvent and alcohol is solute and when both components are in liquid phase then a larger amount of component (water) is solvent and shorter amount of component (alcohol) will mix with each other to form a solution.
Volume of solute(alcohol)

= 5.6 mL

Volume of solvent

= 75 mL

Volume of solution = volume of solute + volume of solvent
=

5.6 + 75

=

80.6 mL

Percentage (by volume) of alcohol

= \frac{Volume of alcohol}{Total volume of solution} \times 100

\Rightarrow

=

\frac{5.6}{80.6} \times 100

\Rightarrow

=

6.95 %

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