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A solution is 0.1 Min formic acid $(K_{a} = 2.0 \times 10^{- 4} M)$ . and 0.1 Min hydrofluoric acid $(K_{a} = 8.0 \times 10^{- 4} M)$ . Its pH will be about

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Correct option is A

${[H_{3} O^{+}] = (K_{1} c_{1} + K_{2} c_{2}) = [(2.0 \times 10^{- 4} M) (0.1 M) + (8.0 \times 10^{- 4} M)) (0.1 M)]}^{1 / 2} = 1.0 \times 10^{- 2} M pH = - \log (1.0 \times 10^{- 2}) = 2.0$

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A solution is 0.1 Min formic acid Ka=2.0×10−4M. and 0.1 Min hydrofluoric acid Ka=8.0×10−4M. Its pH will be about

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A solution is 0.1 Min formic acid $(K_{a} = 2.0 \times 10^{- 4} M)$ . and 0.1 Min hydrofluoric acid $(K_{a} = 8.0 \times 10^{- 4} M)$ . Its pH will be about