A solution is 0.1M with respect to KCl and 0.2M with respect to MgCl₂. The molarity of Cl^– ions in the solution is

For KCl, the Cl^- concentration as per given molarity =$1\times 0.1M=0.1M$
For MgCl₂, the Cl^- concentration as per the given molarity = $2\times 0.2M=0.4M$
Thus, net molarity of Cl^- in the solution = $0.1+0.4=0.5M$
Hence, correct option is: (D) 0.5M