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A solution is prepared by dissolving 2.8 g of lime (CaO) in enough water to make 1.00 L of lime water $(Ca {(OH)}_{2}$ (aq). If solubility of Ca(OH) 2 in water is 1.48 gm/lt. The pH of the solution obtained will be: [log 2 = 0.3, Ca = 40, 0 = 16, H = 1]

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12.6

1.3

12.3

answer is B.

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Detailed Solution

Here,

$s = \frac{1.48}{74} M; [{OH}^{-}] = 2 s; pOH = 1.4$

Thus,

$\Rightarrow pH = 12.6$

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