A solution is prepared by dissolving a solid mixture of K2C2O4 and KHC2O4. A 10 mL portion of this solution required 10 mL, 0.05 M KOH solution for titration reaction. In a seperate analysis 10 mL, of the same stock solution required 10 mL, 0.06 M acidified KMnO4 solution for titration. Which of the following are correct?

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A solution is prepared by dissolving a solid mixture of $K_{2} C_{2} O_{4}$ and ${KHC}_{2} O_{4}$ . A $10 mL$ portion of this solution required $10 mL, 0.05 M KOH$ solution for titration reaction. In a seperate analysis $10 mL$ , of the same stock solution required $10 mL, 0.06 M$ acidified ${KMnO}_{4}$ solution for titration. Which of the following are correct?

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The original mixture contains $K_{2} C_{2} O_{4}$ and ${KHC}_{2} O_{4}$ in 2:1 molar ratio.

20 mL of the original stock solution require 3 millimoles of acidified dichromate solution for titration

20 mL of the original stock solution requires 6 milli-equivalents of acidified dichromate solution for titration

The original mixture contains $K_{2} C_{2} O_{4}$ and ${KHC}_{2} O_{4}$ in 2:1 molar ratio

answer is A, C.

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Detailed Solution

milli equivalent of ${KHC}_{2} O_{4}$ in $\begin{aligned} 10 mL = 10 \times 0.05 = 0.5 \end{aligned}$

$= mmol of {KHC}_{2} O_{4}$

milli equivalent of $K_{2} C_{2} O_{4}$ + milli equivalent of ${KHC}_{2} O_{4}$ $= 10 \times 0.06 \times 5$ m mol of $K_{2} C_{2} O_{4} \times 2 + 0.5 \times 2 = 3$