Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A solution is prepared by mixing 0.01 mol of each of H2CO3, NaHCO3,Na2CO3 and NaOH in 100 ml of water  PH of resulting solution is nearly _______.
[Pka1andPka2ofH2CO3 are 6.37 and 10.31 respectively.  log2=0.3010] 

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

answer is 10.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

detailed_solution_thumbnail

H2CO3+NaOHNaHCO3+H2O

Millimole             10                  10                 -                    -
At end                   0                   0                  10+10=20.
Final mixture has 20 milli moles NaHCO3and 10 millimoles Na2CO3

PH=Pka2+logsaltAcid[Buffer:Na2CO3+NaHCO3]

PH=10.31+log(1020)

10

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon