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A solution is prepared by mixing 100 ml of 0.1M NH₄OH and 200 ml of 0.2M NH₄Cl. pKb of NH₄OH is 4.8. Then the pH of the solution is

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9.0

8.0

8.5979

5.4021

answer is C.

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Detailed Solution

The P^OHof a basic buffer is given as,

$large {P^{OH}} = {P^{Kb}} + log frac{{left[ {Salt} right]}}{{left[ {Acid} right]}}$

$large {P^{OH}} = 4.8 + log frac{{frac{{200 times 0.2}}{{300}}}}{{frac{{100 times 0.1}}{{300}}}}$

$large {P^{OH}} = 4.8 + log frac{{40}}{{10}}$

$large begin{gathered} {P^{OH}} = 5.4 \ {P^H} = 14 - 5.4 \ end{gathered}$

$large {P^H} = 8.6$

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