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A solution is prepared by mixing 25.0 mL of 6.0 M HCI with 45.0 mL of 3.0 M ${HNO}_{3}$ what is $[H^{+}]$ in the resulting solution ?

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$1.9 M$

$2.1 M$

$4.1 M$

$4.5 M$

answer is C.

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Detailed Solution

$[H^{+}] = \frac{25 \times 6 + 45 \times 3}{25 + 45}$

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