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Q.

A solution is saturated with respect to SrCO3 and SrF2. The CO32 was found to be 1.2×103 M

The concentration of' F in the solution would be

(Given: KspSrCO3=7.0×1010M2 and KspSrF2=7.9×1010M3)

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a

1.3×103 M

b

3.7×102 M

c

5.8×107 M

d

2.6×102 M

answer is B.

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Detailed Solution

Sr2+=KspSrCO3CO32=7.0×1010M21.2×103M=5.8×107M

F=KspSrF2Sr2+1/2=7.9×1010M35.8×107M1/2=3.7×102M

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