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Q.

A solution of a monoprotic weak acid has acidity constant Ka . The minimum initial concentration ‘c’ such that the concentration of the undissociated acid can be equated to ‘c’ within a 10%   limit of error, is y Ka . What is the value of y10?
 (Report the value to nearest integer)
 

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answer is 9.

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Detailed Solution

 HA(aq)H+(aq)+A(aq)
Initially c                0 0
At equilib.   c(1α)   cα   cα

Ka=(cα)2c(1α)=(0.1c)20.9c=0.01c0.9 Ka=0.1c9;c=9Ka0.1=90Ka      
 
 
 

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