A solution of $AgN{O}_3$ was electrolyzed for 10 minutes using a current of 1.2 amperes. What is the amount of silver deposited at cathode?

$A{g}^{+}\left(aq\right)+e^{-}\to Ag\left(s\right)$

According to this reaction we require 1F or $1\times 96500$coulombs to deposit 108g of silver $t=10\times 60=600s,I\text{}=1.2A$

Charge  = $600\times 1.2=720coulombs$

$965000$coulombs deposit 108g

720 coulombs deposit $\frac{720}{96500}\times 108=0.805g$