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A solution of an acid has $pH = 4.70$ . Find out the concentration ${OH}^{-}$ ions $({pK}_{w} = 14)$

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$5 \times 10^{- 10} M$

$4 \times 10^{- 10} M$

$2 \times 10^{- 5} M$

$9 \times 10^{- 4} M$

answer is A.

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Detailed Solution

$pH + pOH = 14$ .

Hence, $pOH = 14 - pH = 14 - 4.70 = 9.30$ .

But $pOH = - \log [OH]^{-}$ .

${IOH}^{-} = 10^{- 9.3} = 5 \times 10^{- 10}$ .

Hence the correct answer (A) $5 \times 10^{- 10} M$ .

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