A solution of copper sulphate (CuSO₄) is electrolysed for 10 minutes with a current of 1.5 amperes. The mass of copper deposited at the cathode (at. mass of Cu = 63u) is

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0.3892 g

0.2938 g

0.2398 g

0.3928 g

answer is B.

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Detailed Solution

W = Zit
where Z = Electrochemical equivalent
Eq. wt. of copper = $= \frac{63}{2} = 31.5$
$Z = \frac{31.5}{96500}$
$W = Z i t = \frac{31.5}{96500} \times 1.5 \times 10 \times 60 = 0.2938 g$

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