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Q.

A solution of Fe2(SO4)3 is electrolyzed for 'x' min with a current of 1.5 A to deposit 0.3482 g of Fe.
The value of x is______. [nearest integer] Given : 1 F = 96500 C mol–1 Atomic mass of Fe = 56 g mol–1

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answer is 20.

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Detailed Solution

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Fe3++3e−⟶Fe 

3F⟶1 mole Fe is deposited  

 For 1g⟶3×9650056 (required charge)  

 For 0.3482g⟶3×9650056×0.3482=1800.06 

Q = it  1800.06 = 1.5 t  

t = 20 min

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