A solution of HCl is prepared by mixing 60 mL of0.12 M HCl and 40 mL of0.25 M HCl solution. The molarity of HCl in the resultant solution is

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0.172M

0.185 M

0.20 M

0.150 M

answer is D.

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Detailed Solution

The molarity of resultant solution will be $M = \frac{M_{1} V_{1} + M_{2} V_{2}}{V_{1} + V_{2}} = \frac{(0.12 M) (60 mL) + (0.25 M) (40 mL)}{(100 mL)} = 0.172 M$

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