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A solution of sucrose in 100 g of water boils at 100.25 °C. If this solution is boiled till its temperature is 101 °C, the mass of water evaporated from the solution is

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By Expert Faculty of Sri Chaitanya
a
25g
b
50g
c
75g
d
85g

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detailed solution

Correct option is C

We have from ΔTb=mKb

ΔTb2ΔTb1=m2m1=n2/mwater 2n2mwater 1=mwater 1mwater 2

Hence, mwater 2=mwater 1ΔTb1/ΔTb2=(100g)(0.25K/1K)=25g.

Mass of water evaporated =100g25g=75g


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