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A solution of sucrose(molar mass == 342 g/mol). is prepared by dissolving 68.4 g of it per litre of the solution, what is its osmotic pressure $(R = 0.082 lit. atm. k^{- 1} {mol}^{- 1})$ at 273 K

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4.48 atm

5.32 atm

4.04 atm

6.02 atm

answer is B.

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Detailed Solution

$\begin{array}{l} π = C R T \\ π = \frac{w \times R \times T}{m V} = \frac{68.4 \times 0.0821 \times 273}{342} = 4.48 atm \end{array}$

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