A solution of two miscible liquids showing negative deviation from Raoult's law will have :

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A solution of two miscible liquids showing negative deviation from Raoult's law will have :

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decreased vapour pressure, decreased boiling point

decreased vapour pressure, increased boiling point

increased vapour pressure, increased boiling point

increased vapour pressure, decreased boiling point

answer is D.

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Detailed Solution

Solution with negative deviation has
$\begin{aligned} P_{T} < P_{A^{0}} X_{A} + P_{B} 0 X_{B} \\ P_{A} < P_{A^{0}} X_{A} \\ P_{B} < P_{B} 0 X_{B} \end{aligned}$
If vapour pressure decreases so boiling point increases.

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