A solution of FeCl3 is M30 Its molarity for Cl− ion will be:

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Q.

A solution of ${FeCl}_{3}$ is $\frac{M}{30}$ Its molarity for ${Cl}^{-}$ ion will be:

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a

$\frac{M}{5}$

b

$\frac{M}{30}$

c

$\frac{M}{10}$

d

$\frac{M}{90}$

answer is C.

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Detailed Solution

Molarity of ${Cl}^{-} = 3 \times (molarity of {FeCl}_{3})$

$= 3 \times (\frac{M}{30}) = \frac{M}{10}$

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